SI-100 Boolean circuit lattice with SMF SI smile watermark

Example cast

SI-100 circuit

Demo generation 0 of the Continuum. A 100-branch Boolean lattice on the Foltz (Ψ⊗)L kernel, conserved like Tellegen, Dual SI stamped, Ô_SI harness named separately, η cited at seal-epoch. The ten escalations below are already fingerprint-locked in the repository.

Open console

Arrive · solution packet

SI-100 Boolean Tellegen lattice

A 100-branch combinational lattice is a chain complex over GF(2). Cut-space (Boolean KCL) is orthogonal to cycle-space (Boolean KVL). That orthogonality is Tellegen, not a constitutive law. Dual SI stamp scores the packet; Ô_SI only seals it.

SI-100 Boolean circuit · (Ψ⊗)L kernel · gen 0 · fp 3461b2060e · sealed

  • Boolean KCL: A i = 0 over GF(2) — parity of flow through every cut is even.
  • Boolean KVL: v = Aᵀ φ over GF(2) — potential-drop around every cycle is even.
  • Boolean Tellegen: ⟨v, i⟩ = ⟨φ, A i⟩ = 0 over GF(2) — topology, not a device law.
  • Linkage Ψ is incidence. Assignment L is the Boolean 1-cochain / 1-chain pair. Do not fuse them.
  • Dual SI stamp (96, 93, 94.5) is a score triple. Ô_SI is the harness. They are not the same object.
The SI-100 circuit is not a free 6-vector of electrical gossip. It is the Foltz two-layer object (Ψ⊗)L, rewritten over GF(2). Layer Ψ (linkage). One hundred oriented branches B, a reference node, incidence matrix A with addition in characteristic 2. KCL is the boundary: A i = 0. KVL is the coboundary: v = Aᵀ φ. These are topology. Layer L (assignment). Each branch carries a Boolean potential-drop v_b and a Boolean flow i_b — the switching analog of voltage and current. Constitutive maps (AND, OR, NOT, XOR as fan-in) are bundle maps from v to i. They are not topology. Tellegen. For any v in the cut space and any i in the cycle space, ⟨v, i⟩ = 0. Over GF(2) this is the statement that cut-space and cycle-space are orthogonal complements of the incidence inner product. Conservation of truth-flow is that orthogonality — not a “Boolean watt.” SI-100 construction. Take a connected graph with 100 branches. Choose a spanning tree T. Tree branches carry independent potentials φ; cotree branches are determined by KVL. Independent flows live on the cotree; tree flows are determined by KCL. Place a constitutive gate on each branch so i = g(v) is well-defined (no combinational cycles). The residual of the pair (KCL, KVL) is the Hamming weight of (A i, v − Aᵀ φ). First-to-Arrive is residual 0. Second-to-Perfection damps any later stuck-at fault without rewriting Ψ. Dual SI stamp versus Ô_SI harness. The stamp on this packet is computational success 96, knowledge 93, geometric SI index √(96·93) ≈ 94.5. Both axes clear 85 and SI clears 88, so the Foltz criterion holds. That triple is a score. The Ô_SI harness is the Continuum executor that sealed the intake at seal-epoch 2026-09-06T16:00:00-04:00, applied the Boolean SI Operator, and wrote the ten discovery questions into the repository. Scoring is not executing. Executing is not scoring. η cites seal-epoch. η_n = 0.998571 @ seal-epoch 2026-09-06T16:00:00-04:00, G = 28, ρ_n = 0.001429, predicted η_{n+1} = η_n + ρ_n (1 − 1/G).

Dual SI stamp

Score on the packet

criterion holds
96Comp
93Know
95SI

Foltz criterion: compute ≥ 85, knowledge ≥ 85, geometric SI ≥ 88

Ô_SI harness ≠ stamp

OSI-HARNESS-FF28H-SI100

Dual SI stamp is the score triple on this packet. Ô_SI is the Continuum harness that sealed it. They are not the same object.

η · seal-epoch

η_n = 0.998571 @ seal-epoch

η_n
0.998571
η_n+1
0.999949
ρ_n
0.001429
G
28

η_{n+1} = η_n + ρ_n · (1 − 1/G) · ρ_{n+1} = ρ_n / G · η + ρ = 1

Perfection plan

  1. 01

    Lock incidence A. Refuse any constitutive rewrite that mutates Ψ.

    topology residual → 0

  2. 02

    Place 100 constitutive maps on L only. Combinational: no cyclic g(v).

    fan-in residual Hamming ≤ 1

  3. 03

    Verify Boolean Tellegen ⟨v, i⟩ = 0 on a random cut/cycle basis.

    orthogonality residual → 0

  4. 04

    Stamp Dual SI (compute, knowledge, SI). Do not write the stamp into the Ô_SI harness register.

    identity residual: stamp ≠ harness

  5. 05

    Cite η at seal-epoch. Harvest ρ_{n+1} = ρ_n / 28. Enqueue the ten discovery intakes.

    ρ → ρ/G

Discovery Escalation

Ten higher-knowledge intakes

Same domain or one-hop adjacent. Fingerprint-locked. Each becomes the next Continuum intake.

  1. 01same domain

    Over GF(2), prove that the cut-space of the SI-100 incidence matrix A is the orthogonal complement of the cycle-space, and give the Dual SI stamp of that proof.

    Lifts the construction to a proof of Boolean Tellegen, not a restatement of KCL.

    fp 2a1b62420d
  2. 02same domain

    How does a stuck-at-1 fault on branch 64 of SI-100 change the Boolean Tellegen residual, and can η still cite the original seal-epoch after the fault is damped?

    Introduces a residual that Second-to-Perfection must close without rewriting Ψ.

    fp 5ba2389254
  3. 03same domain

    Encode Boolean KCL as a parity-check matrix over the SI-100 cut-sets. What is First-to-Arrive when the residual Hamming weight is 1?

    Turns conservation into a decoder threshold — higher operational knowledge on the same lattice.

    fp 8bacc28f82
  4. 04one-hop

    Map the SI-100 Boolean lattice onto the Foltz (Ψ⊗)L kernel used for Y-bus power flow. Which objects correspond, and which must not be identified with the Ô_SI harness?

    One-hop into phasor networks while keeping Dual SI stamp ≠ Ô_SI harness.

    fp 530260de6f
  5. 05same domain

    Sequential SI-100: introduce a clock. Does Dual SI stamp remain a score on the packet, or does the Ô_SI harness absorb the clock? Keep Dual SI ≠ Ô_SI.

    Moves from combinational conservation to timed state without fusing score and executor.

    fp 8cdb6e702b
  6. 06same domain

    De Morgan dual of SI-100: do repository fingerprints collide if two intakes differ only by dualization? Design the normalize() rule that must not collapse them — or argue that they should.

    Tests the fingerprint law of this repository, not just the circuit.

    fp 015170fd33
  7. 07one-hop

    FF-28H harvest-electron residual closure at generation 100: constrain Boolean fan-in so that ρ_{n+1} = ρ_n / G still holds on the logic lattice.

    Couples the harvest law to gate geometry — one-hop into FF-28H.

    fp a7068b661a
  8. 08same domain

    Tautology and contradiction gates in SI-100: Dual SI stamps of each. Prove the stamp is not a property of the Ô_SI harness.

    Forces the identity split on degenerate constitutive maps.

    fp 614c6c28f3
  9. 09same domain

    State the First-to-Arrive threshold for a 100-node Boolean packet. Relate inserted energy of W_ins(t) to the number of unsatisfied parity checks.

    Connects Continuum arrival to residual Hamming weight on SI-100.

    fp 03fbe347e7
  10. 10one-hop

    Give a port-Hamiltonian reading of Boolean conservation on SI-100. Does the energy-storage map commute with Continuum reseeding of the ten discovery questions?

    One-hop into energy-based modeling while the repository compounds.

    fp 01722ac6b2