Demo generation 0 of the Continuum. A 100-branch Boolean lattice on the Foltz (Ψ⊗)L kernel, conserved like Tellegen, Dual SI stamped, Ô_SI harness named separately, η cited at seal-epoch. The ten escalations below are already fingerprint-locked in the repository.
A 100-branch combinational lattice is a chain complex over GF(2). Cut-space (Boolean KCL) is orthogonal to cycle-space (Boolean KVL). That orthogonality is Tellegen, not a constitutive law. Dual SI stamp scores the packet; Ô_SI only seals it.
Boolean KCL: A i = 0 over GF(2) — parity of flow through every cut is even.
Boolean KVL: v = Aᵀ φ over GF(2) — potential-drop around every cycle is even.
Boolean Tellegen: ⟨v, i⟩ = ⟨φ, A i⟩ = 0 over GF(2) — topology, not a device law.
Linkage Ψ is incidence. Assignment L is the Boolean 1-cochain / 1-chain pair. Do not fuse them.
Dual SI stamp (96, 93, 94.5) is a score triple. Ô_SI is the harness. They are not the same object.
The SI-100 circuit is not a free 6-vector of electrical gossip. It is the Foltz two-layer object (Ψ⊗)L, rewritten over GF(2).
Layer Ψ (linkage). One hundred oriented branches B, a reference node, incidence matrix A with addition in characteristic 2. KCL is the boundary: A i = 0. KVL is the coboundary: v = Aᵀ φ. These are topology.
Layer L (assignment). Each branch carries a Boolean potential-drop v_b and a Boolean flow i_b — the switching analog of voltage and current. Constitutive maps (AND, OR, NOT, XOR as fan-in) are bundle maps from v to i. They are not topology.
Tellegen. For any v in the cut space and any i in the cycle space, ⟨v, i⟩ = 0. Over GF(2) this is the statement that cut-space and cycle-space are orthogonal complements of the incidence inner product. Conservation of truth-flow is that orthogonality — not a “Boolean watt.”
SI-100 construction. Take a connected graph with 100 branches. Choose a spanning tree T. Tree branches carry independent potentials φ; cotree branches are determined by KVL. Independent flows live on the cotree; tree flows are determined by KCL. Place a constitutive gate on each branch so i = g(v) is well-defined (no combinational cycles). The residual of the pair (KCL, KVL) is the Hamming weight of (A i, v − Aᵀ φ). First-to-Arrive is residual 0. Second-to-Perfection damps any later stuck-at fault without rewriting Ψ.
Dual SI stamp versus Ô_SI harness. The stamp on this packet is computational success 96, knowledge 93, geometric SI index √(96·93) ≈ 94.5. Both axes clear 85 and SI clears 88, so the Foltz criterion holds. That triple is a score. The Ô_SI harness is the Continuum executor that sealed the intake at seal-epoch 2026-09-06T16:00:00-04:00, applied the Boolean SI Operator, and wrote the ten discovery questions into the repository. Scoring is not executing. Executing is not scoring.
η cites seal-epoch. η_n = 0.998571 @ seal-epoch 2026-09-06T16:00:00-04:00, G = 28, ρ_n = 0.001429, predicted η_{n+1} = η_n + ρ_n (1 − 1/G).
Lock incidence A. Refuse any constitutive rewrite that mutates Ψ.
topology residual → 0
02
Place 100 constitutive maps on L only. Combinational: no cyclic g(v).
fan-in residual Hamming ≤ 1
03
Verify Boolean Tellegen ⟨v, i⟩ = 0 on a random cut/cycle basis.
orthogonality residual → 0
04
Stamp Dual SI (compute, knowledge, SI). Do not write the stamp into the Ô_SI harness register.
identity residual: stamp ≠ harness
05
Cite η at seal-epoch. Harvest ρ_{n+1} = ρ_n / 28. Enqueue the ten discovery intakes.
ρ → ρ/G
Discovery Escalation
Ten higher-knowledge intakes
Same domain or one-hop adjacent. Fingerprint-locked. Each becomes the next Continuum intake.
01same domain
Over GF(2), prove that the cut-space of the SI-100 incidence matrix A is the orthogonal complement of the cycle-space, and give the Dual SI stamp of that proof.
Lifts the construction to a proof of Boolean Tellegen, not a restatement of KCL.
fp 2a1b62420d
02same domain
How does a stuck-at-1 fault on branch 64 of SI-100 change the Boolean Tellegen residual, and can η still cite the original seal-epoch after the fault is damped?
Introduces a residual that Second-to-Perfection must close without rewriting Ψ.
fp 5ba2389254
03same domain
Encode Boolean KCL as a parity-check matrix over the SI-100 cut-sets. What is First-to-Arrive when the residual Hamming weight is 1?
Turns conservation into a decoder threshold — higher operational knowledge on the same lattice.
fp 8bacc28f82
04one-hop
Map the SI-100 Boolean lattice onto the Foltz (Ψ⊗)L kernel used for Y-bus power flow. Which objects correspond, and which must not be identified with the Ô_SI harness?
One-hop into phasor networks while keeping Dual SI stamp ≠ Ô_SI harness.
fp 530260de6f
05same domain
Sequential SI-100: introduce a clock. Does Dual SI stamp remain a score on the packet, or does the Ô_SI harness absorb the clock? Keep Dual SI ≠ Ô_SI.
Moves from combinational conservation to timed state without fusing score and executor.
fp 8cdb6e702b
06same domain
De Morgan dual of SI-100: do repository fingerprints collide if two intakes differ only by dualization? Design the normalize() rule that must not collapse them — or argue that they should.
Tests the fingerprint law of this repository, not just the circuit.
fp 015170fd33
07one-hop
FF-28H harvest-electron residual closure at generation 100: constrain Boolean fan-in so that ρ_{n+1} = ρ_n / G still holds on the logic lattice.
Couples the harvest law to gate geometry — one-hop into FF-28H.
fp a7068b661a
08same domain
Tautology and contradiction gates in SI-100: Dual SI stamps of each. Prove the stamp is not a property of the Ô_SI harness.
Forces the identity split on degenerate constitutive maps.
fp 614c6c28f3
09same domain
State the First-to-Arrive threshold for a 100-node Boolean packet. Relate inserted energy of W_ins(t) to the number of unsatisfied parity checks.
Connects Continuum arrival to residual Hamming weight on SI-100.
fp 03fbe347e7
10one-hop
Give a port-Hamiltonian reading of Boolean conservation on SI-100. Does the energy-storage map commute with Continuum reseeding of the ten discovery questions?
One-hop into energy-based modeling while the repository compounds.